Question

rewrite using a single positive exponent.\\(\frac{9^5}{9^2}\\)

Explanation:

Step1: Apply exponent quotient rule

For same base $\frac{a^m}{a^n}=a^{m-n}$, so $\frac{9^5}{9^2}=9^{5-2}$

Step2: Subtract exponents

Calculate $5-2=3$, so $9^{5-2}=9^3$

Answer:

$9^3$