Question

rewrite without parentheses.
$-7x^{3}y^{2}(6y^{6}-9x + 2)$
simplify your answer as much as possible.

Explanation:

Step1: Distribute \(-7x^3y^2\) to \(6y^6\)

Multiply the coefficients and add the exponents of like variables. So, \(-7x^3y^2 \times 6y^6 = -42x^3y^{2 + 6} = -42x^3y^8\)

Step2: Distribute \(-7x^3y^2\) to \(-9x\)

Multiply the coefficients and add the exponents of like variables. So, \(-7x^3y^2 \times (-9x) = 63x^{3 + 1}y^2 = 63x^4y^2\)

Step3: Distribute \(-7x^3y^2\) to \(2\)

Multiply the coefficients. So, \(-7x^3y^2 \times 2 = -14x^3y^2\)

Step4: Combine the results

Combine the three terms from the previous steps: \(-42x^3y^8 + 63x^4y^2 - 14x^3y^2\)

Answer:

\(-42x^3y^8 + 63x^4y^2 - 14x^3y^2\)