Question

rhombus lmno is shown with its diagonals. the length of $overline{ln}$ is 28 centimeters. what is the length of $overline{lp}$? 7 cm 9 cm 14 cm 21 cm

Explanation:

Step1: Recall rhombus diagonal property

The diagonals of a rhombus bisect each other. That is, if the diagonals of rhombus LMNO are LN and MO which intersect at point P, then LP = PN and MP = PO.

Step2: Calculate length of LP

Given that LN = 28 cm. Since LP=\frac{1}{2}LN, then LP=\frac{28}{2}=14 cm.

Answer:

14 cm