Sovi.AI - AI Math Tutor

Scan to solve math questions

QUESTION IMAGE

rick kept track of wins and losses for each game attempt in the followi…

Question

rick kept track of wins and losses for each game attempt in the following table.

gameget - it - rolling (a)bag - of - tokens (b)pick - your - tile (c)
number of losses173141175

a. get - it - rolling is a game in which the player rolls an eight - sided die. the player wins if the die lands on 5.
b. bag - of - tokens is a game in which the player draws a token from a bag containing 7 tokens, each of a different color. the player wins if they draw the red token.
c. pick - your - tile is a game in which the player picks a number tile from a box of 12 tiles, each with a different number on it. the player wins if they pick the tile that has the number 9 on it.
select the correct statement.
a. the results from both game a and game c align closely with the theoretical probability of winning those games, while the results from game b do not.
b. only the results from game a align closely with the theoretical probability of winning that game.
c. only the results from game b align closely with the theoretical probability of winning that game.
d. the results from both game b and game c align closely with the theoretical probability of winning those games, while the results from game a do not.

Explanation:

Step1: Calculate theoretical probabilities

For Get - It - Rolling (A), probability of winning is $\frac{1}{8}$ since there is 1 favorable outcome (rolling a 5 on an eight - sided die) out of 8 possible outcomes. For Bag - of - Tokens (B), probability of winning is $\frac{1}{7}$ as there is 1 favorable token out of 7. For Pick - Your - Tile (C), probability of winning is $\frac{1}{12}$ as there is 1 favorable tile out of 12.

Step2: Calculate experimental probabilities

For game A, experimental probability of winning $P(A)=\frac{26}{26 + 173}=\frac{26}{199}\approx0.131$. For game B, experimental probability of winning $P(B)=\frac{54}{54+141}=\frac{54}{195}\approx0.277$. For game C, experimental probability of winning $P(C)=\frac{17}{17 + 175}=\frac{17}{192}\approx0.089$.

Step3: Analyze alignment

The experimental probability of game B ($\approx0.277$) is relatively close to its theoretical probability ($\frac{1}{7}\approx0.143$) compared to the other games. The experimental probability of game A ($\approx0.131$) and game C ($\approx0.089$) do not align as closely with their theoretical probabilities.

Answer:

B. Only the results from game A align closely with the theoretical probability of winning that game.