Question

a rocket is fired upward from the ground with an initial velocity of 280 feet per second. neglecting air resistance, the height of the rocket at any time t can be described in feet by the polynomial - 16t² + 280t. find the height of the rocket at t = 2 seconds.

time, t (in seconds) | height - 16t² + 280t
2 | (simplify your answer.)

Explanation:

Step1: Substitute t = 2 into the formula

Substitute \(t = 2\) into \(-16t^{2}+280t\), we get \(-16\times2^{2}+280\times2\).

Step2: Calculate the power part

First calculate \(2^{2}=4\), then \(-16\times4=-64\).

Step3: Calculate the multiplication part

Calculate \(280\times2 = 560\).

Step4: Calculate the sum

\(-64 + 560=496\).

Answer:

496