Question

run the function that you just created (\get_h\), and t works in the cell below.
since the function returns the result (instead of printing the result), you need to create a new variable to store the value returned by your function. and then print out the value of this new variable to see whether it is what you expected.
for example, if you provide the values as a=3 and b=4, the value returned by your function should be 5.0.

Explanation:

To solve this, we'll assume the get_h function is for calculating the hypotenuse (using the Pythagorean theorem, \( h = \sqrt{a^2 + b^2} \)) as the example with \( a = 3 \), \( b = 4 \), and result \( 5.0 \) suggests. Here's the Python code to run the function, store the result, and print it:

Step 1: Define the get_h function (if not already defined)

Let's define the function first. If it's already defined, you can skip this step.

def get_h(a, b):
    import math
    return math.sqrt(a**2 + b**2)

Step 2: Call the function, store the result, and print it

We'll call get_h with \( a = 3 \) and \( b = 4 \) (as in the example), store the result in a variable, and then print the variable.

# Call the function and store the result
result = get_h(3, 4)
# Print the result
print(result)

When you run this code, the output will be 5.0, which matches the expected result from the example.

If your get_h function is for a different purpose, you would adjust the function definition and the arguments passed to it, but the general process of calling the function, storing the result, and printing it remains the same.

For example, if you want to use different values for a and b, say \( a = 5 \) and \( b = 12 \), you would change the function call to:

result = get_h(5, 12)
print(result)

This would output 13.0 (since \( \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \)).

Answer:

To solve this, we'll assume the get_h function is for calculating the hypotenuse (using the Pythagorean theorem, \( h = \sqrt{a^2 + b^2} \)) as the example with \( a = 3 \), \( b = 4 \), and result \( 5.0 \) suggests. Here's the Python code to run the function, store the result, and print it:

Step 1: Define the get_h function (if not already defined)

Let's define the function first. If it's already defined, you can skip this step.

def get_h(a, b):
    import math
    return math.sqrt(a**2 + b**2)

Step 2: Call the function, store the result, and print it

We'll call get_h with \( a = 3 \) and \( b = 4 \) (as in the example), store the result in a variable, and then print the variable.

# Call the function and store the result
result = get_h(3, 4)
# Print the result
print(result)

When you run this code, the output will be 5.0, which matches the expected result from the example.

If your get_h function is for a different purpose, you would adjust the function definition and the arguments passed to it, but the general process of calling the function, storing the result, and printing it remains the same.

For example, if you want to use different values for a and b, say \( a = 5 \) and \( b = 12 \), you would change the function call to:

result = get_h(5, 12)
print(result)

This would output 13.0 (since \( \sqrt{5^2 + 12^2} = \sqrt{25 + 144} = \sqrt{169} = 13 \)).