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Question
sai is rearranging his furniture. he wants his couch to sit along the 20 - foot wall, labeled ac on the diagram. he wants the ratio of ab to bc is 1:2. what distance from the left side of the wall should sai place the left side of his couch? a) 6 ft 8 in. b) 10 ft c) 13 ft 4 in. d) 16 ft
Step1: Let the distance $AB = x$ and $BC = y$.
We know that $\frac{x}{y}=\frac{1}{2}$, so $y = 2x$. Also, $x + y=20$ ft.
Step2: Substitute $y = 2x$ into $x + y=20$.
We get $x+2x=20$, which simplifies to $3x = 20$. Then $x=\frac{20}{3}$ ft. Since $1$ ft=$12$ in, $\frac{20}{3}$ ft=$6$ ft and $\frac{2}{3}\times12 = 8$ in.
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A. 6 ft 8 in.