Question

*sam jumped from a plane. his acceleration was -9.8 m/s². he hit the ground in 30 seconds. what was his velocity just before he hit the ground? 0.32 m/s 3.1 m/s -294 m/s 294 m/s

Explanation:

Step1: Recall the velocity - acceleration - time formula

The formula for velocity $v$ in terms of acceleration $a$ and time $t$ when the initial velocity $u = 0$ is $v=u + at$. Here, $u = 0\ m/s$, $a=- 9.8\ m/s^{2}$, and $t = 30\ s$.

Step2: Substitute the values into the formula

$v=0+( - 9.8)\times30$.
$v=-294\ m/s$.

Answer:

C. -294 m/s