Question

a sample of blood pressure measurements is taken from a data set and those values (mm hg) are listed below. the values are matched so that subjects each have systolic and diastolic measurements. find the mean and median for each of the two samples and then compare the two sets of results. are the measures of center the best statistics to use with these data? what else might be better? find the means. the mean for systolic is □ mm hg and the mean for diastolic is □ mm hg. (type integers or decimals rounded to one decimal place as needed.) systolic: 114, 96, 146, 109, 121, 139, 97, 137, 117, 118 diastolic: 57, 74, 59, 56, 87, 58, 91, 69, 54, 76

Explanation:

Step1: Calculate sum of systolic values

Systolic values: 114, 98, 146, 109, 121, 139, 97, 137, 117, 118
Sum = \(114 + 98 + 146 + 109 + 121 + 139 + 97 + 137 + 117 + 118\)
= \(114+98=212\); \(212+146=358\); \(358+109=467\); \(467+121=588\); \(588+139=727\); \(727+97=824\); \(824+137=961\); \(961+117=1078\); \(1078+118=1196\)

Step2: Find mean of systolic

Number of values (\(n\)) = 10
Mean = \(\frac{1196}{10} = 119.6\)

Step3: Calculate sum of diastolic values

Diastolic values: 57, 74, 59, 56, 87, 58, 91, 69, 54, 76
Sum = \(57 + 74 + 59 + 56 + 87 + 58 + 91 + 69 + 54 + 76\)
= \(57+74=131\); \(131+59=190\); \(190+56=246\); \(246+87=333\); \(333+58=391\); \(391+91=482\); \(482+69=551\); \(551+54=605\); \(605+76=681\)

Step4: Find mean of diastolic

Mean = \(\frac{681}{10} = 68.1\)

Answer:

The mean for systolic is \(119.6\) mm Hg and the mean for diastolic is \(68.1\) mm Hg.