Question

score: 0/10
$\frac{d}{dx}(x^{-3})$
answer
$-\frac{1}{4}x^{-4}$ $-3x^{-2}$ $-\frac{1}{2}x^{-2}$ $-3x^{-4}$

Explanation:

Step1: Apply power rule for derivatives

The power rule states $\frac{d}{dx}(x^n) = nx^{n-1}$. Here, $n=-3$.
$\frac{d}{dx}(x^{-3}) = -3x^{-3-1}$

Step2: Simplify the exponent

Calculate the new exponent value.
$-3x^{-3-1} = -3x^{-4}$

Answer:

$-3x^{-4}$