Question

score: 2/10 current time: 36.6
find: tan b
right triangle with vertical leg 15, horizontal leg 36, hypotenuse 39, right angle at bottom left, angle b at top left, angle a at bottom right
\the figure is not drawn to scale\
answer
options:
\\(\frac{36}{15}\\),
\\(\frac{15}{36}\\),
\\(\frac{36}{39}\\),
\\(\frac{15}{39}\\)

Explanation:

Step1: Recall tangent definition

In a right triangle, $\tan\theta = \frac{\text{opposite}}{\text{adjacent}}$ to $\theta$.

Step2: Identify sides for $\angle B$

For $\angle B$, opposite side is $36$, adjacent side is $15$.

Step3: Calculate $\tan B$

$\tan B = \frac{\text{opposite to } B}{\text{adjacent to } B} = \frac{36}{15}$

Answer:

$\frac{36}{15}$ (corresponding to the first option: $\frac{36}{15}$)