Question

select all the equations where $x = 3$ is a solution.
choose 2 answers:
a $x + 4 = 7$
b $dfrac{x}{9} = 3$
c $5 - x = 2$
d $8x = 32$
e $x - 10 = 7$

Explanation:

for Option A:

Step1: Substitute \( x = 3 \) into \( x + 4 \)

\( 3 + 4 = 7 \), which matches the right - hand side of the equation \( x + 4 = 7 \). So \( x = 3 \) is a solution for option A.

for Option B:

Step1: Substitute \( x = 3 \) into \( \frac{x}{9} \)

\( \frac{3}{9}=\frac{1}{3}
eq3 \). So \( x = 3 \) is not a solution for option B.

for Option C:

Step1: Substitute \( x = 3 \) into \( 5 - x \)

\( 5-3 = 2 \), which matches the right - hand side of the equation \( 5 - x = 2 \). So \( x = 3 \) is a solution for option C.

for Option D:

Step1: Substitute \( x = 3 \) into \( 8x \)

\( 8\times3 = 24
eq32 \). So \( x = 3 \) is not a solution for option D.

Answer:

A. \( x + 4 = 7 \)
C. \( 5 - x = 2 \)