Question

select the correct answer from the drop - down menu.
the table shows the results from a survey of 335 randomly selected households with pets. this survey was conducted by a new pet store that is opening nearby.

	have children	do not have children	total
2 pets	85	41	126
3 or more pets	46	72	118
total	169	166	335

the pet store uses the data to make decisions about inventory. complete the given statement.
a customer is more likely to have 1 pet and no children than they are to have
options: 3 pets and children, 2 pets and children, 3 pets and no children

Explanation:

Step1: Calculate 1 pet, no children prob

$\frac{53}{335} \approx 0.158$

Step2: Calculate 3 pets, children prob

$\frac{46}{335} \approx 0.137$

Step3: Calculate 2 pets, children prob

$\frac{85}{335} \approx 0.254$

Step4: Calculate 3 pets, no children prob

$\frac{72}{335} \approx 0.215$

Step5: Compare probabilities

$0.158 > 0.137$, $0.158 < 0.254$, $0.158 < 0.215$

Answer:

3 pets and children