Question

select the correct answer from each drop - down menu. a group of people were surveyed, and the data about their age and whether they have an iron deficiency was recorded in the two - way frequency table. (the two - way frequency table is as follows: iron deficiency \\ age, less than 20 years: yes - 41, no - 109, total - 150; 20 - 30 years: yes - 37, no - 43, total - 80; more than 30 years: yes - 24, no - 46, total - 70; total: yes - 102, no - 198, total - 300) based on the data in the table, the probability of randomly choosing a person who has iron deficiency and is less than 20 years old is 0.14. the probability of randomly choosing a person who does not have iron deficiency and is 20 years old or more is (the drop - down menu has options 0.15, 0.23, 0.3).

Explanation:

Step1: Identify target group count

Find total people with no iron deficiency and aged 20+: sum 43 + 46 = 89

Step2: Identify total survey size

Total surveyed people = 300

Step3: Calculate probability

$\text{Probability} = \frac{89}{300} \approx 0.3$

Answer:

0.3