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Question
select the correct locations on the tables. the table below would represent a proportional relationship except for one y - value. identify which y - value prevents the table from representing a proportional relationship. then, select the value that would make the table proportional. alternate values 17 10 18.5 19.5 20
Step1: Find the constant of proportionality for first three pairs
For the first pair $(x = 1.5,y = 6)$, the ratio $\frac{y}{x}=\frac{6}{1.5}=4$. For the second pair $(x = 2,y = 8)$, $\frac{y}{x}=\frac{8}{2}=4$. For the third pair $(x = 4,y = 16)$, $\frac{y}{x}=\frac{16}{4}=4$.
Step2: Check the fourth and fifth pairs
For the fourth pair $(x = 4.5,y = 16.5)$, $\frac{y}{x}=\frac{16.5}{4.5}=\frac{165}{45}=\frac{11}{3}
eq4$. For the fifth pair $(x = 7,y = 28)$, $\frac{y}{x}=\frac{28}{7}=4$. So the $y -$value that prevents proportionality is $16.5$.
Step3: Find the correct $y -$value
If the relationship is proportional with a constant of proportionality $k = 4$ and $x=4.5$, then $y=k\times x=4\times4.5 = 18$.
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The $y -$value that prevents proportionality is $16.5$. The value that would make the table proportional is $18$.