Question

select the x - intercept(s) and y - intercept of the function, if one exists. $f(x)=\frac{x + 1}{-x^{2}-2x + 8}$ y - int: none x - int: (-1, 0) x - int: ($\frac{1}{8}$, 0) y - int: (0, $\frac{1}{8}$) x - int: none y - int: (0, -1)

Explanation:

Step1: Find the x - intercept

Set $y = f(x)=0$. Since a fraction is zero when its numerator is zero and denominator is non - zero, set $x + 1=0$.
$x+1 = 0\Rightarrow x=-1$.

Step2: Find the y - intercept

Set $x = 0$. Then $f(0)=\frac{0 + 1}{-0^{2}-2\times0 + 8}=\frac{1}{8}$.

Answer:

$x - int:(-1,0)$; $y - int:(0,\frac{1}{8})$