Question

a series circuit contains two devices, one with a resistance of 10 ohms and one with a resistance of 4 ohms. if the generator supplies a voltage of 42 v, whats the magnitude of the current?

Explanation:

Step1: Find total resistance in series

In a series circuit, total resistance \( R_{total} = R_1 + R_2 \). Given \( R_1 = 10\ \Omega \), \( R_2 = 4\ \Omega \), so \( R_{total} = 10 + 4 = 14\ \Omega \).

Step2: Use Ohm's Law to find current

Ohm's Law is \( I = \frac{V}{R} \), where \( V = 42\ V \), \( R = R_{total} = 14\ \Omega \). So \( I = \frac{42}{14} = 3\ A \).

Answer:

The magnitude of the current is \( 3\) amperes.