Question

a set of data has a normal distribution with a mean of 60 and a standard deviation of 6. find the percent of data within the following interval from 32 to 62. 18. what is the z - score for the given interval in
(show all work in a dry - erase.)

Explanation:

Step1: Calculate z-scores for bounds

First z-score: $z_1 = \frac{37 - 53}{8} = \frac{-16}{8} = -2$
Second z-score: $z_2 = \frac{69 - 53}{8} = \frac{16}{8} = 2$

Step2: Apply empirical rule

For normal distributions, ~95% of data lies within $z=-2$ to $z=2$.

Answer:

95%