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in sheep, the allele for white wool (w) is dominant, and the allele for…

Question

in sheep, the allele for white wool (w) is dominant, and the allele for black wool (w) is recessive. if a heterozygous white sheep is crossed with a homozygous black sheep, how many different genotypes are possible and what are they?

Explanation:

Step1: Determine Genotypes of Parents

The heterozygous white sheep has genotype \( Ww \) (since \( W \) is dominant for white, \( w \) for black). The homozygous black sheep has genotype \( ww \) (as \( w \) is recessive and homozygous means two recessive alleles).

Step2: Set Up Punnett Square

\( W \)\( w \)
\( w \)\( Ww \)\( ww \)

From the Punnett square, we can see the possible genotypes.

Step3: Identify Possible Genotypes

Looking at the Punnett square, the offspring can have two genotypes: \( Ww \) (heterozygous white) and \( ww \) (homozygous black). So there are 2 different genotypes.

Answer:

There are 2 different genotypes, which are \( Ww \) and \( ww \).