Question

show that (3x - 1)(x + 5) is equivalent to 3x^2 + 14x - 5. type or show your response in one of the spaces below.

Explanation:

Step1: Apply FOIL method

$(3x - 1)(x + 5)=3x\times x+3x\times5-1\times x - 1\times5$

Step2: Simplify each term

$3x\times x = 3x^{2}$, $3x\times5=15x$, $-1\times x=-x$, $-1\times5 = - 5$
So, $3x^{2}+15x - x-5$

Step3: Combine like - terms

$15x - x=14x$, then $3x^{2}+14x - 5$

Answer:

Since expanding $(3x - 1)(x + 5)$ using the FOIL method results in $3x^{2}+14x - 5$, they are equivalent.