Question

to show that △qrp≅△psr by sss, what must be the value of x? x = choose

Explanation:

Step1: Set equal corresponding sides

For $\triangle QRP$ and $\triangle PSR$ to be congruent by SSS (Side - Side - Side), we set $QR = PS$. So, $2x + 3=4x - 7$.

Step2: Solve the equation for $x$

First, subtract $2x$ from both sides: $2x+3 - 2x=4x - 7-2x$, which simplifies to $3 = 2x-7$. Then add 7 to both sides: $3 + 7=2x-7 + 7$, getting $10 = 2x$. Divide both sides by 2: $\frac{10}{2}=\frac{2x}{2}$, so $x = 5$.

Answer:

$5$