QUESTION IMAGE
Question
similarity - same shape, different size
3 types
aa (congruent angles)
sas (2 ratios, one angle)
sss (3 side ratios)
- δvut - δefg
- δuts - δcde
Problem 3: $\triangle VUT \sim \triangle EFG$
Step 1: Identify corresponding sides
For similar triangles $\triangle VUT$ and $\triangle EFG$, we need to find the ratios of corresponding sides. Let's list the side lengths:
- $\triangle VUT$: $VU = 35$, $UT = 49$, $VT = 42$
- $\triangle EFG$: $EF = 20$, $FG = 28$, $EG = 24$
Step 2: Calculate ratios of corresponding sides
- Ratio of $EF$ to $VU$: $\frac{EF}{VU} = \frac{20}{35} = \frac{4}{7}$
- Ratio of $EG$ to $VT$: $\frac{EG}{VT} = \frac{24}{42} = \frac{4}{7}$
- Ratio of $FG$ to $UT$: $\frac{FG}{UT} = \frac{28}{49} = \frac{4}{7}$
Since all ratios are equal ($\frac{4}{7}$), the triangles are similar by SSS (Side - Side - Side) similarity criterion.
Problem 4: $\triangle UTS \sim \triangle CDE$
Step 1: Identify corresponding angles and sides
We know that $\angle U = 63^{\circ}$ and $\angle C = 63^{\circ}$, so $\angle U=\angle C$. Now, let's list the side lengths:
- $\triangle UTS$: $UT = 72$, $US = 66$
- $\triangle CDE$: $CD = 60$, $CE = 55$
Step 2: Calculate ratios of corresponding sides
- Ratio of $CD$ to $UT$: $\frac{CD}{UT}=\frac{60}{72}=\frac{5}{6}$
- Ratio of $CE$ to $US$: $\frac{CE}{US}=\frac{55}{66}=\frac{5}{6}$
Since we have a pair of equal angles ($\angle U = \angle C$) and the ratios of the including sides are equal ($\frac{5}{6}$), the triangles are similar by SAS (Side - Angle - Side) similarity criterion.
For the SAS Similarity Example (with the 30° angle)
Step 1: Identify sides and angle
We have two triangles. The smaller triangle has sides 5 and 6 with an included 30° angle. The larger triangle has sides 10 and 12 with an included 30° angle.
Step 2: Calculate ratios of corresponding sides
- Ratio of 10 to 5: $\frac{10}{5}=2$
- Ratio of 12 to 6: $\frac{12}{6}=2$
Since the ratio of the two pairs of corresponding sides is equal (2) and the included angle (30°) is equal, the triangles are similar by SAS (Side - Angle - Side) similarity criterion.
For the SSS Similarity Example (with sides 5, 6, 7 and 10, 14,?)
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Step 1: Identify angles
We have two triangles. Let's assume that in the smaller triangle we can identify two angles (let's say $\angle A$ and $\angle B$) and in the larger triangle, the corresponding angles are equal (because of the AA similarity - if two angles of one triangle are equal to two angles of another triangle, the triangles are similar).
Step 2: Conclude similarity
Since two angles of one triangle are equal to two angles of the other triangle, by the AA (Angle - Angle) similarity criterion, the triangles are similar. This also implies they are similar by AAA (since the sum of angles in a triangle is 180°, if two angles are equal, the third is also equal) and since similar triangles have the same shape, the AA criterion is sufficient for similarity.