Question

1. simplify by cancellation, if possible. multiply (-11/5)·(-45/99)= 90/99 1 1/3 7/9 1 7) simplify by cancellation, if possible. multiply. 22/13·(-2/12)·7/2= -77/78 -38/39 -1 5/6 -1

Explanation:

Step1: Multiply the numerators and denominators

For \((-\frac{11}{5})\cdot(-\frac{45}{99})\), when multiplying two fractions \(\frac{a}{b}\cdot\frac{c}{d}=\frac{a\cdot c}{b\cdot d}\). Here \(a=- 11\), \(b = 5\), \(c=-45\), \(d = 99\). So \((-\frac{11}{5})\cdot(-\frac{45}{99})=\frac{(-11)\times(-45)}{5\times99}\). The product of two negative numbers is positive, so \((-11)\times(-45)=495\), and the fraction becomes \(\frac{495}{495}\).

Step2: Simplify the fraction

\(\frac{495}{495}=1\)

Step1: Multiply the fractions

For \(\frac{22}{13}\cdot(-\frac{2}{12})\cdot\frac{7}{2}\), first multiply \(\frac{22}{13}\cdot(-\frac{2}{12})\). \(\frac{22}{13}\cdot(-\frac{2}{12})=\frac{22\times(- 2)}{13\times12}=-\frac{44}{156}\). Then multiply the result by \(\frac{7}{2}\), so \(-\frac{44}{156}\cdot\frac{7}{2}=\frac{-44\times7}{156\times2}\).

Step2: Simplify the numerator and denominator

\(-44\times7=-308\) and \(156\times2 = 312\). The fraction is \(-\frac{308}{312}\). Divide both the numerator and denominator by 4, we get \(-\frac{77}{78}\)

Answer:

1