Question

simplify. express your answer as a single term, without a denominator.
$t^{-8}u^{0} \cdot t^{-3}u^{0}$

Explanation:

Step1: Apply zero exponent rule

Any non-zero number to the 0 power is 1.
$u^0 = 1$, $u^0 = 1$
So the expression becomes: $t^{-8} \cdot 1 \cdot t^{-3} \cdot 1 = t^{-8} \cdot t^{-3}$

Step2: Add exponents like bases

When multiplying like bases, add exponents: $a^m \cdot a^n = a^{m+n}$
$t^{-8 + (-3)} = t^{-11}$

Step3: Remove negative exponent

Rewrite negative exponent as positive term (no denominator): $a^{-n} = a^{-n}$ (since we avoid denominators, we keep the negative exponent as required)

Answer:

$t^{-11}$