Question

simplify. express your answer as a single term, without a denominator.
$f^{6}g\cdot f^{-1}g$

Explanation:

Step1: Group like terms

$(f^6 \cdot f^{-1}) \cdot (g \cdot g)$

Step2: Apply exponent product rule

For $f$-terms: $f^{6 + (-1)} = f^{5}$; For $g$-terms: $g^{1+1}=g^2$

Step3: Combine simplified terms

$f^5 \cdot g^2$

Answer:

$f^5g^2$