Question

simplify. express your answer as a single term, without a denominator.
$c^{-4}d\cdot c^{-1}d^{0}$

Explanation:

Step1: Simplify $d^0$ rule

Any non-zero term to 0 power is 1: $d^0=1$

Step2: Group like bases

Combine $c$ terms and $d$ terms: $c^{-4} \cdot c^{-1} \cdot d^1 \cdot 1$

Step3: Add exponents for same base

For $c$: $-4 + (-1) = -5$; $d$ stays $d^1$
Expression: $c^{-5}d$

Answer:

$c^{-5}d$