Question

simplify. express your answer as a single term, without a denominator.
$q^{-1}r^{8} \cdot q^{-8}r$

Explanation:

Step1: Group like bases

$q^{-1} \cdot q^{-8} \cdot r^{8} \cdot r$

Step2: Apply exponent product rule

For $q$: $q^{-1 + (-8)} = q^{-9}$; For $r$: $r^{8 + 1} = r^{9}$

Answer:

$q^{-9}r^{9}$