Question

simplify. express your answer using a single exp ((j^{3})^{-3})

Explanation:

Step1: Recall exponent rule \((a^m)^n = a^{m\times n}\)

For \((j^{3})^{-3}\), apply the rule: \(m = 3\), \(n=-3\), so we calculate \(3\times(-3)\).

Step2: Calculate the exponent

\(3\times(-3)= - 9\), so \((j^{3})^{-3}=j^{-9}\) (or if we want positive exponent, \(j^{-9}=\frac{1}{j^{9}}\), but since the problem says "using a single exp" (probably "exponent"), both are single exponents, but following the rule application directly, \(j^{-9}\) is a single exponent form.

Answer:

\(j^{-9}\) (or \(\frac{1}{j^{9}}\) is also correct, but \(j^{-9}\) is a single exponent expression as well)