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Question
simplify. express your answer using a single exponent.\\((c^{-8})^{-3}\\)
Step1: Recall exponent rule \((a^m)^n = a^{m\times n}\)
For \((c^{-8})^{-3}\), apply the rule: \(m = -8\), \(n = -3\), so we calculate \(-8\times(-3)\).
Step2: Calculate the product of exponents
\(-8\times(-3)=24\), so \((c^{-8})^{-3}=c^{24}\).
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\(c^{24}\)