Question

simplify the expression. \\(\frac{27y^8z^5}{-3y^4z^2}\\)

Explanation:

Step1: Simplify the coefficients

$\frac{27}{-3} = -9$

Step2: Simplify the $y$ terms

$\frac{y^8}{y^4} = y^{8-4} = y^4$

Step3: Simplify the $z$ terms

$\frac{z^5}{z^2} = z^{5-2} = z^3$

Step4: Combine all simplified parts

$-9 \times y^4 \times z^3$

Answer:

$-9y^4z^3$
(First box: $-9$, Second box: $4$, Third box: $3$)