Question

simplify the expression.
$2d^2 + 3d + 4 + d - d^2 + 8 - d$
$\square d^2 + \square d + \square$

Explanation:

Step1: Combine $d^2$ terms

$2d^2 - d^2 = (2-1)d^2 = d^2$

Step2: Combine $d$ terms

$3d + d - d = (3+1-1)d = 3d$

Step3: Combine constant terms

$4 + 8 = 12$

Answer:

$1d^2 + 3d + 12$
(The blanks are filled with 1, 3, 12 respectively)