Question

simplify.
$2x^{9} \cdot 6v^{8}y \cdot 3v^{-6}y^{-2}x^{-8}$
use only positive exponents in your answer.

Explanation:

Step1: Group like terms

$(2 \cdot 6 \cdot 3) \cdot (x^9 \cdot x^{-8}) \cdot (v^8 \cdot v^{-6}) \cdot (y \cdot y^{-2})$

Step2: Multiply coefficients

$2 \cdot 6 \cdot 3 = 36$

Step3: Combine $x$-terms (add exponents)

$x^{9 + (-8)} = x^{1} = x$

Step4: Combine $v$-terms (add exponents)

$v^{8 + (-6)} = v^{2}$

Step5: Combine $y$-terms (add exponents)

$y^{1 + (-2)} = y^{-1} = \frac{1}{y}$

Step6: Multiply all simplified terms

$36 \cdot x \cdot v^2 \cdot \frac{1}{y}$

Answer:

$\frac{36 x v^2}{y}$