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sixty high school students were surveyed about the type of books they p…

Question

sixty high school students were surveyed about the type of books they prefer to read. the results are shown in the table below. what is the probability of a student preferring a mystery book, given that the student is a freshman?
freshmen mystery humor nonfiction
freshmen 5 6 3
sophomores 6 5 2
juniors 9 7 5
seniors 7 2 3
types of books preferred by high school students
options: \\(\frac{7}{30}\\), \\(\frac{5}{27}\\), \\(\frac{5}{14}\\), \\(\frac{1}{12}\\)

Explanation:

Step1: Find total freshmen

Sum freshmen's book preferences: \(5 + 6 + 3 = 14\)

Step2: Find mystery - preferring freshmen

From table, freshmen who like mystery: \(5\)

Step3: Calculate conditional probability

Use formula \(P(\text{Mystery}|\text{Freshman})=\frac{\text{Freshmen - Mystery}}{\text{Total Freshmen}}=\frac{5}{14}\)? Wait, no, wait: Wait, freshmen total is \(5 + 6 + 3 = 14\)? Wait, no, 5 (mystery) +6 (humor)+3 (nonfiction) = 14? Wait, but let's recalculate: 5+6=11, 11+3=14. Then the number of freshmen who like mystery is 5. So the probability is \(\frac{5}{14}\)? Wait, no, wait the options: one of the options is \(\frac{5}{14}\)? Wait the options are \(\frac{7}{30}\), \(\frac{5}{27}\), \(\frac{5}{14}\), \(\frac{1}{12}\). Wait, let's check again. Wait, freshmen: mystery 5, humor 6, nonfiction 3. So total freshmen: 5+6+3=14. Number of freshmen who like mystery: 5. So conditional probability \(P(\text{Mystery} | \text{Freshman})=\frac{\text{Number of freshmen who like mystery}}{\text{Total number of freshmen}}=\frac{5}{14}\). Wait, but let me check the table again. Freshmen row: Mystery 5, Humor 6, Nonfiction 3. So total freshmen: 5+6+3=14. So yes, 5/14. Wait but the option is \(\frac{5}{14}\)? Wait the third option is \(\frac{5}{14}\)? Wait the user's options: third one is \(\frac{5}{14}\). So that's the answer.

Wait, maybe I made a mistake. Wait, let's re - express:

Conditional probability formula: \(P(A|B)=\frac{P(A\cap B)}{P(B)}\). In this case, \(A\) is "prefers mystery", \(B\) is "is a freshman". \(A\cap B\) is the number of freshmen who prefer mystery, which is 5. \(P(B)\) is the number of freshmen, which is \(5 + 6 + 3=14\). So \(P(A|B)=\frac{5}{14}\).

Answer:

\(\frac{5}{14}\) (corresponding to the option with \(\frac{5}{14}\))