Question

the size of a cell is typically found by capturing an image under a microscope then using software to measure its diameter. two cells are measured using this method:
cell h: $9.47 \times 10^{-3}$ centimeters
cell k: $8.5 \times 10^{-4}$ centimeters
how many times larger is the diameter of cell h than the diameter of cell k? write your answer in standard notation, rounding to the nearest tenth.

Explanation:

Step1: Set up division equation

$\frac{9.47 \times 10^{-3}}{8.5 \times 10^{-4}}$

Step2: Split into coefficient/exponent parts

$\frac{9.47}{8.5} \times \frac{10^{-3}}{10^{-4}}$

Step3: Calculate coefficient division

$\frac{9.47}{8.5} \approx 1.114$

Step4: Simplify exponent division

$\frac{10^{-3}}{10^{-4}} = 10^{-3 - (-4)} = 10^{1} = 10$

Step5: Multiply results and round

$1.114 \times 10 = 11.14 \approx 11.1$

Answer:

11.1