Question

if the sodium - potassium pump was mistakenly transporting 3 potassium toys from inside the cell to outside, and 2 sodium toys from outside to inside, what would be the most immediate consequence for the cell? the cell would continue transporting ions normally despite the mistake the cell would immediately start accumulating potassium outside while losing sodium from inside the cell would immediately start accumulating sodium inside while losing potassium from outside the cell would stop transporting any ions until the mistake was corrected

Explanation:

The sodium - potassium pump normally transports 3 sodium ions out of the cell and 2 potassium ions into the cell. In this case, 3 potassium ions are transported out and 2 sodium ions are transported in. So, the cell will immediately start accumulating sodium inside while losing potassium from inside (since potassium is moving out and sodium is moving in).

Answer:

The cell would immediately start accumulating sodium inside while losing potassium from inside