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Question
solution sets of quadratic equations quick check
ariel is trying to determine if ( x = -3 ) is a solution to the quadratic equation ( -3x^2 - 9x = 0 ). which explanation demonstrates the correct reasoning? (1 point)
- yes, ( x = -3 ) is a solution because substituting it back into the equation results in the following
this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true
| ( x ) | substituted | evaluate | true statement? |
|---|
- yes, ( x = -3 ) is a solution because substituting it back into the equation results in the following:
this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true
| ( x ) | substituted | evaluate | true statement? |
|---|
- no, ( x = -3 ) is not a solution because substituting it back into the equation results in the following
this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true
| ( x ) | substituted | evaluate | true statement? |
|---|
eq 0 ) | false |
- no, ( x = -3 ) is not a solution because substituting it back into the equation results in the following
this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true
| ( x ) | substituted | evaluate | true statement? |
|---|
eq 0 ) | false |
Step1: Substitute \( x = -3 \) into the equation \( -3x^2 - 9x = 0 \)
First, calculate \( x^2 \) when \( x = -3 \): \( (-3)^2 = 9 \). Then substitute into the left - hand side of the equation:
\( -3\times(-3)^2-9\times(-3)=-3\times9 + 27 \)
Step2: Evaluate the expression
Calculate \( -3\times9=-27 \), then \( -27 + 27 = 0 \). So when \( x=-3 \), the left - hand side of the equation \( -3x^2 - 9x \) equals \( 0 \), which is equal to the right - hand side of the equation.
Now let's analyze each option:
- Option 1: The evaluation \( 54 = 0 \) is wrong. Because \( -3\times(-3)^2-9\times(-3)=-27 + 27 = 0
eq54 \).
- Option 2: When we substitute \( x = -3 \) into \( -3x^2-9x \), we have \( -3\times(-3)^2-9\times(-3)=-3\times9 + 27=-27 + 27 = 0 \), so \( 0 = 0 \) is a true statement. This means \( x=-3 \) is a solution.
- Option 3: The evaluation \( -54
eq0 \) is wrong. The correct result of \( -3\times(-3)^2-9\times(-3) \) is \( 0 \), not \( -54 \).
- Option 4: The evaluation \( 54
eq0 \) is wrong. The correct result of \( -3\times(-3)^2-9\times(-3) \) is \( 0 \), not \( 54 \).
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Yes, \( x=-3 \) is a solution because substituting it back into the equation results in the following:
This table shows the evaluation of an expression for a specific value of \( x \), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true
| \( x \) | Substituted | Evaluate | True Statement? |
|---|