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solution sets of quadratic equations quick check ariel is trying to det…

Question

solution sets of quadratic equations quick check
ariel is trying to determine if ( x = -3 ) is a solution to the quadratic equation ( -3x^2 - 9x = 0 ). which explanation demonstrates the correct reasoning? (1 point)

  • yes, ( x = -3 ) is a solution because substituting it back into the equation results in the following

this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true

( x )substitutedevaluatetrue statement?
  • yes, ( x = -3 ) is a solution because substituting it back into the equation results in the following:

this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true

( x )substitutedevaluatetrue statement?
  • no, ( x = -3 ) is not a solution because substituting it back into the equation results in the following

this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true

( x )substitutedevaluatetrue statement?

eq 0 ) | false |

  • no, ( x = -3 ) is not a solution because substituting it back into the equation results in the following

this table shows the evaluation of an expression for a specific value of ( x ), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true

( x )substitutedevaluatetrue statement?

eq 0 ) | false |

Explanation:

Step1: Substitute \( x = -3 \) into the equation \( -3x^2 - 9x = 0 \)

First, calculate \( x^2 \) when \( x = -3 \): \( (-3)^2 = 9 \). Then substitute into the left - hand side of the equation:
\( -3\times(-3)^2-9\times(-3)=-3\times9 + 27 \)

Step2: Evaluate the expression

Calculate \( -3\times9=-27 \), then \( -27 + 27 = 0 \). So when \( x=-3 \), the left - hand side of the equation \( -3x^2 - 9x \) equals \( 0 \), which is equal to the right - hand side of the equation.

Now let's analyze each option:

  • Option 1: The evaluation \( 54 = 0 \) is wrong. Because \( -3\times(-3)^2-9\times(-3)=-27 + 27 = 0

eq54 \).

  • Option 2: When we substitute \( x = -3 \) into \( -3x^2-9x \), we have \( -3\times(-3)^2-9\times(-3)=-3\times9 + 27=-27 + 27 = 0 \), so \( 0 = 0 \) is a true statement. This means \( x=-3 \) is a solution.
  • Option 3: The evaluation \( -54

eq0 \) is wrong. The correct result of \( -3\times(-3)^2-9\times(-3) \) is \( 0 \), not \( -54 \).

  • Option 4: The evaluation \( 54

eq0 \) is wrong. The correct result of \( -3\times(-3)^2-9\times(-3) \) is \( 0 \), not \( 54 \).

Answer:

Yes, \( x=-3 \) is a solution because substituting it back into the equation results in the following:

This table shows the evaluation of an expression for a specific value of \( x \), demonstrating the substitution, the resulting calculation, and the confirmation that the statement is true

\( x \)SubstitutedEvaluateTrue Statement?