Question

1.) the solution to a system of equations is (5, -19). choose two equations that might make the system.
a. $y = -3x - 6$
b. $y = 2x - 23$
c. $y = -7x + 16$
d. $y = x - 17$
e. $y = -2x - 9$
solve the system of equations:.
$\

$$\begin{cases} y = 4x - 3 \\\\ y = 2x + 9 \\end{cases}$$

$

Explanation:

Step1: Test point (5,-19) in A

Substitute $x=5, y=-19$ into $y=-3x-6$:
$\text{Right side} = -3(5)-6 = -15-6 = -21
eq -19$

Step2: Test point (5,-19) in B

Substitute $x=5, y=-19$ into $y=2x-23$:
$\text{Right side} = 2(5)-23 = 10-23 = -13
eq -19$

Step3: Test point (5,-19) in C

Substitute $x=5, y=-19$ into $y=-7x+16$:
$\text{Right side} = -7(5)+16 = -35+16 = -19 = y$

Step4: Test point (5,-19) in D

Substitute $x=5, y=-19$ into $y=x-17$:
$\text{Right side} = 5-17 = -12
eq -19$

Step5: Test point (5,-19) in E

Substitute $x=5, y=-19$ into $y=-2x-9$:
$\text{Right side} = -2(5)-9 = -10-9 = -19 = y$

Answer:

C. $y = -7x + 16$, E. $y = -2x - 9$