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solve for n. 6(n + 6) ≥ -18

Question

solve for n.
6(n + 6) ≥ -18

Explanation:

Step1: Expand the left - hand side

$6(n + 6)=6n+36$, so the inequality becomes $6n + 36\geq - 18$.

Step2: Subtract 36 from both sides

$6n+36 - 36\geq - 18-36$, which simplifies to $6n\geq - 54$.

Step3: Divide both sides by 6

$\frac{6n}{6}\geq\frac{-54}{6}$, so $n\geq - 9$.

Answer:

$n\geq - 9$