Question

solve (-g + 2(3 + g) = -4(g + 1)). check your solution. enter your answer as an integer or decimal.
(g =)

Explanation:

Step1: Expand both sides

$-g + 2\times3 + 2\times g = -4\times g -4\times1$
$\implies -g + 6 + 2g = -4g -4$

Step2: Simplify left side

$(-g+2g) + 6 = -4g -4$
$\implies g + 6 = -4g -4$

Step3: Move g terms to left

$g + 4g + 6 = -4$
$\implies 5g + 6 = -4$

Step4: Isolate constant terms

$5g = -4 -6$
$\implies 5g = -10$

Step5: Solve for g

$g = \frac{-10}{5}$
$\implies g = -2$

Step6: Verify solution

Substitute $g=-2$ into original equation:
Left side: $-(-2)+2(3+(-2))=2+2(1)=4$
Right side: $-4(-2+1)=-4(-1)=4$
Both sides are equal, so solution is valid.

Answer:

$g = -2$