Question

solve for d.
4d² - 121 = 0
write each solution as an integer, proper fraction, or improper fraction in simplest form. if there are multiple solutions, separate them with commas.
d =

Explanation:

Step1: Isolate the squared - term

Add 121 to both sides of the equation $4d^{2}-121 = 0$. We get $4d^{2}=121$.

Step2: Solve for $d^{2}$

Divide both sides of the equation $4d^{2}=121$ by 4. So, $d^{2}=\frac{121}{4}$.

Step3: Find the values of $d$

Take the square - root of both sides. Remember, when $x^{2}=a$ ($a\geq0$), $x=\pm\sqrt{a}$. So, $d=\pm\sqrt{\frac{121}{4}}=\pm\frac{11}{2}$.

Answer:

$d = \frac{11}{2},-\frac{11}{2}$