Question

solve \\(\frac{x - 1}{x + 3} = 1\\) and \\(\frac{x - 1}{x + 3} > 1\\) analytically. then use a graphing calculator to graph and solve \\(\frac{x - 1}{x + 3} < 1\\). select the correct choice below and, if necessary, fill in the answer box to complete your choice. \\(\bigcirc\\) a. the solution set to \\(\frac{x - 1}{x + 3} = 1\\) is \\(\\{\square\\}\\). (use a comma to separate answers as needed.) \\(\bigcirc\\) b. there is no solution.

Explanation:

Step1: Multiply both sides by \(x + 3\) (note \(x

eq - 3\))
\(\frac{x - 1}{x + 3}\times(x + 3)=1\times(x + 3)\)
\(x-1=x + 3\)

Step2: Subtract \(x\) from both sides

\(x-1-x=x + 3-x\)
\(-1 = 3\)
This is a contradiction, so there is no solution.

Answer:

B. There is no solution.