Question

solve the compound inequality. 4y - 6 ≤ -14 or 2y + 1 > 7. graph the solution on the number line. if there is no solution, click on
o solution\.

Explanation:

Step1: Solve the first inequality

Add 6 to both sides of $4y - 6\leq - 14$: $4y\leq - 14 + 6$, so $4y\leq - 8$. Then divide both sides by 4, we get $y\leq - 2$.

Step2: Solve the second inequality

Subtract 1 from both sides of $2y+1 > 7$: $2y>7 - 1$, so $2y>6$. Then divide both sides by 2, we get $y > 3$.

Answer:

The solution is $y\leq - 2$ or $y>3$. On the number - line, we have a closed circle at $y = - 2$ and an arrow pointing to the left for $y\leq - 2$, and an open circle at $y = 3$ and an arrow pointing to the right for $y>3$.