Question

solve the equation $7^n \cdot 7^8 = \frac{1}{7}$ for $n$.
$n = \square$

Explanation:

Step1: Combine left side exponents

$7^{n+8} = \frac{1}{7}$

Step2: Rewrite right side as power of 7

$7^{n+8} = 7^{-1}$

Step3: Set exponents equal

$n+8 = -1$

Step4: Solve for n

$n = -1 - 8$

Answer:

$-9$