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Question
- solve the equation $y^3 = \frac{64}{729}$. show your work and explain your steps.
Step1: Take cube root of both sides
$$y = \sqrt[3]{\frac{64}{729}}$$
Step2: Split root into numerator/denominator
$$y = \frac{\sqrt[3]{64}}{\sqrt[3]{729}}$$
Step3: Evaluate cube roots
$\sqrt[3]{64}=4$, $\sqrt[3]{729}=9$, so $y = \frac{4}{9}$
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$y = \frac{4}{9}$