Question

solve the equation using inverse functions.
e^{3z} = 15
enter your answer rounded to the nearest tenth in the box.
z \approx \square

Explanation:

Step1: Apply natural log to both sides

$\ln(e^{3z}) = \ln(15)$

Step2: Simplify left-hand side

$3z = \ln(15)$

Step3: Isolate z, solve for value

$z = \frac{\ln(15)}{3} \approx \frac{2.708}{3} \approx 0.9$

Answer:

$z \approx 0.9$