Question

solve for x
$2\sqrt{x+3}-10=8$
then find the value of $x-10$

Explanation:

Step1: Isolate the radical term

Add 10 to both sides.
$2\sqrt{x+3} = 8 + 10$
$2\sqrt{x+3} = 18$

Step2: Simplify the radical term

Divide both sides by 2.
$\sqrt{x+3} = \frac{18}{2}$
$\sqrt{x+3} = 9$

Step3: Eliminate the square root

Square both sides of the equation.
$(\sqrt{x+3})^2 = 9^2$
$x + 3 = 81$

Step4: Solve for x

Subtract 3 from both sides.
$x = 81 - 3$
$x = 78$

Step5: Calculate x-10

Substitute x=78 into the expression.
$x - 10 = 78 - 10$
$x - 10 = 68$

Answer:

68