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solve the following absolute value inequality: $7 + |3x - 1| \\leq 6$

Question

solve the following absolute value inequality:
$7 + |3x - 1| \leq 6$

Explanation:

Step1: Isolate the absolute value term

Subtract 7 from both sides.
$$|3x - 1| \leq 6 - 7$$
$$|3x - 1| \leq -1$$

Step2: Analyze absolute value property

The absolute value of any real number is non-negative, meaning $|a| \geq 0$ for all real $a$. A non-negative value cannot be less than or equal to a negative number.

Answer:

No solution (or $\emptyset$)