Question

solve the following compound inequality. 18r + 6 < 24 or 7r - 9 > 12 r < ? or r >

Explanation:

Step1: Solve \(18r + 6 < 24\)

Subtract 6 from both sides: \(18r + 6 - 6 < 24 - 6\)
Simplify: \(18r < 18\)
Divide both sides by 18: \(\frac{18r}{18} < \frac{18}{18}\)
Simplify: \(r < 1\)

Step2: Solve \(7r - 9 > 12\)

Add 9 to both sides: \(7r - 9 + 9 > 12 + 9\)
Simplify: \(7r > 21\)
Divide both sides by 7: \(\frac{7r}{7} > \frac{21}{7}\)
Simplify: \(r > 3\)

Answer:

\(r < 1\) OR \(r > 3\)