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Question
solve the following compound inequality. 4m + 6 < 2 or $\frac{m + 4}{3}>3$ m < ? or m >
Step1: Solve the first inequality
Subtract 6 from both sides of $4m + 6<2$:
$4m+6 - 6<2 - 6$, which simplifies to $4m<-4$. Then divide both sides by 4: $m < - 1$.
Step2: Solve the second inequality
Multiply both sides of $\frac{m + 4}{3}>3$ by 3: $m + 4>9$. Then subtract 4 from both sides: $m>5$.
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$m < - 1$ or $m>5$