Question

solve the following inequality algebraically.
$|x + 9| < 6$
answer attempt 1 out of 2

Explanation:

Step1: Apply absolute value inequality rule

For $|A| < b$ where $b>0$, rewrite as $-b < A < b$.
$-6 < x + 9 < 6$

Step2: Subtract 9 from all parts

Isolate $x$ by subtracting 9.
$-6 - 9 < x < 6 - 9$

Step3: Simplify all terms

Calculate the resulting inequalities.
$-15 < x < -3$

Answer:

$-15 < x < -3$